Java编程 已知数组a[6]={8,5,4,2,0,9},请使用for循环来对数组从小到大排序
Java编程 已知数组a[6]={8,5,4,2,0,9},请使用for循环来对数组进行排序,从小~
int r = 0;
for(int i = 0; i < 5; i++){
if(a[i] > a[i+1]){
r = a[i];
a[i] = a[i+1];
a[i+1] = r;
}
}
请看图,利用Arrays类即可.
int[] arrays= {11,2,3,43,54,6,7,8,9};
从小到大
for(int i=0;i<arrays.length;i++){
for(int j=0;j<i;j++){
if(arrays[i]<arrays[j]){
int tmp = arrays[j];
arrays[j]=arrays[i];
arrays[i]=tmp;
}
}
}
从大到小,只要
if(arrays[i]<arrays[j])
改成
if(arrays[i]>arrays[j])
就行
import java.util.Arrays;
public class Test
{
public static void main(String[] args)
{
int a[] = new int[]{8,5,4,2,0,9};
Arrays.sort(a);
System.out.println("排序结果是:");
for(int i=0;i<a.length;i++)
{
System.out.print(a[i]+" ");
}
}
}
int r = 0;
for(int i = 0; i < 5; i++){
if(a[i] > a[i+1]){
r = a[i];
a[i] = a[i+1];
a[i+1] = r;
}
}